function md5cycle(x, k) { var a = x[0], b = x[1], c = x[2], d = x[3] a = ff(a, b, c, d, k[0], 7, -680876936) d = ff(d, a, b, c, k[1], 12, -389564586) c = ff(c, d, a, b, k[2], 17, 606105819) b = ff(b, c, d, a, k[3], 22, -1044525330) a = ff(a, b, c, d, k[4], 7, -176418897) d = ff(d, a, b, c, k[5], 12, 1200080426) c = ff(c, d, a, b, k[6], 17, -1473231341) b = ff(b, c, d, a, k[7], 22, -45705983) a = ff(a, b, c, d, k[8], 7, 1770035416) d = ff(d, a, b, c, k[9], 12, -1958414417) c = ff(c, d, a, b, k[10], 17, -42063) b = ff(b, c, d, a, k[11], 22, -1990404162) a = ff(a, b, c, d, k[12], 7, 1804603682) d = ff(d, a, b, c, k[13], 12, -40341101) c = ff(c, d, a, b, k[14], 17, -1502002290) b = ff(b, c, d, a, k[15], 22, 1236535329) a = gg(a, b, c, d, k[1], 5, -165796510) d = gg(d, a, b, c, k[6], 9, -1069501632) c = gg(c, d, a, b, k[11], 14, 643717713) b = gg(b, c, d, a, k[0], 20, -373897302) a = gg(a, b, c, d, k[5], 5, -701558691) d = gg(d, a, b, c, k[10], 9, 38016083) c = gg(c, d, a, b, k[15], 14, -660478335) b = gg(b, c, d, a, k[4], 20, -405537848) a = gg(a, b, c, d, k[9], 5, 568446438) d = gg(d, a, b, c, k[14], 9, -1019803690) c = gg(c, d, a, b, k[3], 14, -187363961) b = gg(b, c, d, a, k[8], 20, 1163531501) a = gg(a, b, c, d, k[13], 5, -1444681467) d = gg(d, a, b, c, k[2], 9, -51403784) c = gg(c, d, a, b, k[7], 14, 1735328473) b = gg(b, c, d, a, k[12], 20, -1926607734) a = hh(a, b, c, d, k[5], 4, -378558) d = hh(d, a, b, c, k[8], 11, -2022574463) c = hh(c, d, a, b, k[11], 16, 1839030562) b = hh(b, c, d, a, k[14], 23, -35309556) a = hh(a, b, c, d, k[1], 4, -1530992060) d = hh(d, a, b, c, k[4], 11, 1272893353) c = hh(c, d, a, b, k[7], 16, -155497632) b = hh(b, c, d, a, k[10], 23, -1094730640) a = hh(a, b, c, d, k[13], 4, 681279174) d = hh(d, a, b, c, k[0], 11, -358537222) c = hh(c, d, a, b, k[3], 16, -722521979) b = hh(b, c, d, a, k[6], 23, 76029189) a = hh(a, b, c, d, k[9], 4, -640364487) d = hh(d, a, b, c, k[12], 11, -421815835) c = hh(c, d, a, b, k[15], 16, 530742520) b = hh(b, c, d, a, k[2], 23, -995338651) a = ii(a, b, c, d, k[0], 6, -198630844) d = ii(d, a, b, c, k[7], 10, 1126891415) c = ii(c, d, a, b, k[14], 15, -1416354905) b = ii(b, c, d, a, k[5], 21, -57434055) a = ii(a, b, c, d, k[12], 6, 1700485571) d = ii(d, a, b, c, k[3], 10, -1894986606) c = ii(c, d, a, b, k[10], 15, -1051523) b = ii(b, c, d, a, k[1], 21, -2054922799) a = ii(a, b, c, d, k[8], 6, 1873313359) d = ii(d, a, b, c, k[15], 10, -30611744) c = ii(c, d, a, b, k[6], 15, -1560198380) b = ii(b, c, d, a, k[13], 21, 1309151649) a = ii(a, b, c, d, k[4], 6, -145523070) d = ii(d, a, b, c, k[11], 10, -1120210379) c = ii(c, d, a, b, k[2], 15, 718787259) b = ii(b, c, d, a, k[9], 21, -343485551) x[0] = add32(a, x[0]) x[1] = add32(b, x[1]) x[2] = add32(c, x[2]) x[3] = add32(d, x[3]) } function cmn(q, a, b, x, s, t) { a = add32(add32(a, q), add32(x, t)) return add32((a << s) | (a >>> (32 - s)), b) } function ff(a, b, c, d, x, s, t) { return cmn((b & c) | ((~b) & d), a, b, x, s, t) } function gg(a, b, c, d, x, s, t) { return cmn((b & d) | (c & (~d)), a, b, x, s, t) } function hh(a, b, c, d, x, s, t) { return cmn(b ^ c ^ d, a, b, x, s, t) } function ii(a, b, c, d, x, s, t) { return cmn(c ^ (b | (~d)), a, b, x, s, t) } function md51(s) { txt = "" var n = s.length, state = [1732584193, -271733879, -1732584194, 271733878], i for (i = 64; i <= s.length; i += 64) { md5cycle(state, md5blk(s.substring(i - 64, i))) } s = s.substring(i - 64) var tail = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] for (i = 0; i < s.length; i++) tail[i >> 2] |= s.charCodeAt(i) << ((i % 4) << 3) tail[i >> 2] |= 0x80 << ((i % 4) << 3) if (i > 55) { md5cycle(state, tail) for (i = 0; i < 16; i++) tail[i] = 0 } tail[14] = n * 8 md5cycle(state, tail) return state } /* there needs to be support for Unicode here, * unless we pretend that we can redefine the MD-5 * algorithm for multi-byte characters (perhaps * by adding every four 16-bit characters and * shortening the sum to 32 bits). Otherwise * I suggest performing MD-5 as if every character * was two bytes--e.g., 0040 0025 = @%--but then * how will an ordinary MD-5 sum be matched? * There is no way to standardize text to something * like UTF-8 before transformation; speed cost is * utterly prohibitive. The JavaScript standard * itself needs to look at this: it should start * providing access to strings as preformed UTF-8 * 8-bit unsigned value arrays. */ function md5blk(s) { /* I figured global was faster. */ var md5blks = [], i /* Andy King said do it this way. */ for (i = 0; i < 64; i += 4) { md5blks[i >> 2] = s.charCodeAt(i) + (s.charCodeAt(i + 1) << 8) + (s.charCodeAt(i + 2) << 16) + (s.charCodeAt(i + 3) << 24) } return md5blks } var hex_chr = "0123456789abcdef".split("") function rhex(n) { var s = "", j = 0 for (; j < 4; j++) s += hex_chr[(n >> (j * 8 + 4)) & 0x0F] + hex_chr[(n >> (j * 8)) & 0x0F] return s } function hex(x) { for (var i = 0; i < x.length; i++) x[i] = rhex(x[i]) return x.join("") } function md5(s) { return hex(md51(s)) } /* this function is much faster, so if possible we use it. Some IEs are the only ones I know of that need the idiotic second function, generated by an if clause. */ function add32(a, b) { return (a + b) & 0xFFFFFFFF } if (md5("hello") != "5d41402abc4b2a76b9719d911017c592") { function add32(x, y) { var lsw = (x & 0xFFFF) + (y & 0xFFFF), msw = (x >> 16) + (y >> 16) + (lsw >> 16) return (msw << 16) | (lsw & 0xFFFF) } }