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35 lines
474 B
C++
35 lines
474 B
C++
//求矩阵各行元素之和
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#include<stdio.h>
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#include<string.h>
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int main()
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{
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int m, n, i, j, k;
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//输入两个正整数: m*n
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scanf("%d %d", &m, &n);
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int a[m][n];
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//记录每行的n个数的和
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int b[100]= {0};
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for(i=0;i<m;i++)
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{
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for(j=0;j<n;j++)
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{
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scanf("%d",&a[i][j]);
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}
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}
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//每行输出对应矩阵行元素之和
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k=0;
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for(i=0;i<m;i++)
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{
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for(j=0;j<n;j++)
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{
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b[k]+=a[i][j];
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}
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k++;
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}
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for(i=0;i<m;i++)
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{
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printf("%d\n",b[i]);
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}
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return 0;
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}
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